How is half-life period of a initial concentration for a second order reaction ?

Explanation

`t_(1//2)propa^(1-n)`. For `n=2,t_(1//2)prop a^(-1),i.e., t_(1//2)prop(1)/(a)`. Thus, half-life period of a second order reaction is inversely proportional to the initial concentration of nth order,
`t_(1//2)prop(1)/([A_(0)]^(n-1))" Hence, "t_(1//2)prop(1)/([A]_(0))` when n = 2.