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The inactivation of a viral preparation ...

The inactivation of a viral preparation in a chemical bath is found to be first order reaction. If in the beginning, `2.5%` of the virus is inactivated per minute, calculate the rate constant of the viral inactivation.

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`(-d[A])/(dt)=k[A]" or "k=(-1)/([A])(d[A])/(dt)`
It is given that `(d[A])/(A)=(2.5)/(100)" in "dt=60" s ":.k=(2.5)/(100)xx(1)/(60)s^(-1)=4.16xx10^(-4)s^(-1)`
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