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For a consecutive reaction R(1)overset(k...

For a consecutive reaction `R_(1)overset(k_(1))to R_(2)overset(k_(2))to R_(3)`, if initial concentration of `R_(1)` is 100 M and `k_(1):k_(2)=1:0.15`, calculate the value of `t_("max")("Given "k_(1)=4.0xx10^(-2)"min"^(-1)).`

Text Solution

Verified by Experts

`t_("max")` represents time corresponding to maximum concentration of the intermediate `R_(2)`
The value of `t_("max")` is given by the relation
`t_("max")=(2.303)/((k_(1)-k_(2)))log""(k_(1))/(k_(2))`
`k_(1)=4.0xx10^(-2)`
`:.k_(2)=4.0xx10^(-2)xx0.15=6xx10^(-3)`
`:.t_("max")=(2.303)/((4-0.6)10^(-2))log""(4xx10^(-2))/(6xx10^(-3))=(2.303)/(3.4xx10^(-2))xx0.82=55.6" min"`
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