Home
Class 12
CHEMISTRY
In an adsorption experiment, a graph bet...

In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log `(x/m)` axis was found to be `0.3010` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `0.5` atm` .

Text Solution

Verified by Experts

According to Freundlich equation, `x/m =k P^(1//) or log ""(x)/(m)=log k+1/n log P`
`therefore` Plot of `x/m` varsus log P is linear with slope `=1/n` and intercept `=log k.` Thus,
`1/n = tna theta = tan 45^(@)=1 or n=1`
`log k =0.3010 or k= "Antilig" 0.3010=2`
At `P =0.5 atm, x/m =k P^(1//n)=2xx(0.5)^(1)=1.0`
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS|5 Videos

  • SURFACE CHEMISTRY

    PRADEEP|Exercise COMPETITION FOCUS (MULTIPLE CHOICE QUESTIONS) (I. ADSORPTION)|17 Videos

  • SURFACE CHEMISTRY

    PRADEEP|Exercise HIGHER ORDER THINKING SKILLS (HOTS QUESTIONS)|7 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (VIII. Assertion-Reason Type Questions)(Type II)|13 Videos

Similar Questions

Explore conceptually related problems

In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45^(@) . The intercept on the log y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.

In an adsorption experiment a graph between log x/m versus log P was fond to be linear with a slope of 45^@) . The intercept on the log x/m axis was found to 0.70 . Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 1 atm [log5=0.70]

In an Adsorption experiment a graph between log x//m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x//m was found to be 0.3010 . Calculate the amount of gas adsorbed per gm of charcoal under a pressure of 0.6 bar.

A graph between log (x/m) and log p is straight line at an angle of 45^(@) with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

When a graph is pplotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent:

When a graph is plotted between log x//m and log p, it is striaght line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent?