Which of the following compounds exists ?

Options

A. `KHCl_(2)`
B. `KHF_(2)`
C. `KHBr_(2)`
D. `KHI_(2)`

Explanation

To determine which of the given compounds exists, we will analyze each compound based on their chemical properties and the concept of hydrogen bonding.

### Step-by-Step Solution:

1. **List the Compounds**: The compounds given are:
- KHC1₂
- KHF₂
- KHV₂
- KHI₂

2. **Analyze KHF₂**:
- KHF₂ consists of potassium (K), hydrogen (H), and fluorine (F).
- Fluorine is highly electronegative, which allows it to form strong hydrogen bonds with hydrogen.
- The presence of hydrogen bonding makes KHF₂ a stable compound.

3. **Analyze KHC1₂**:
- KHC1₂ consists of potassium (K), hydrogen (H), and chlorine (Cl).
- Chlorine is less electronegative than fluorine, which means it does not form strong hydrogen bonds with hydrogen.
- Therefore, KHC1₂ is less likely to exist.

4. **Analyze KHV₂**:
- KHV₂ consists of potassium (K), hydrogen (H), and vanadium (V).
- Vanadium does not form stable compounds with hydrogen in this context, and thus KHV₂ is unlikely to exist.

5. **Analyze KHI₂**:
- KHI₂ consists of potassium (K), hydrogen (H), and iodine (I).
- Iodine is also less electronegative than fluorine and does not form strong hydrogen bonds with hydrogen.
- Hence, KHI₂ is also unlikely to exist.

6. **Conclusion**:
- Among the compounds analyzed, only KHF₂ exists due to the strong hydrogen bonding that occurs between hydrogen and fluorine.

### Final Answer:
The compound that exists is **KHF₂**.