`SO_(2)` is reducing while `TeO_(2)` is an oxidising agent. Give reasons.

Explanation

To understand why \( SO_2 \) is a reducing agent while \( TeO_2 \) is an oxidizing agent, we need to analyze the oxidation states of sulfur and tellurium in their respective oxides and their tendencies to gain or lose electrons.

### Step-by-Step Solution:

1. **Identify the Oxidation States**:
- In \( SO_2 \), sulfur (S) has an oxidation state of +4.
- In \( TeO_2 \), tellurium (Te) has an oxidation state of +4 as well.

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