`H_(2)S` acts only as a reducing agent while `SO_(2)` acts as an oxidising as well as a reducing agent. Why?

Explanation

To understand why \( H_2S \) acts only as a reducing agent while \( SO_2 \) can act as both an oxidizing and a reducing agent, we need to analyze the oxidation states of sulfur in these compounds.

### Step 1: Determine the oxidation state of sulfur in \( H_2S \)
The formula for hydrogen sulfide is \( H_2S \). To find the oxidation state of sulfur (S), we can set up the following equation based on the overall charge of the molecule being zero:

\[ 2 \times (+1) + X + 0 = 0 \]
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