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Are all the five bonds in PCI(5) equival...

Are all the five bonds in `PCI_(5)` equivalent ? Justify.

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To determine whether all five bonds in phosphorus pentachloride (PCl₅) are equivalent, we need to analyze the molecular structure and hybridization of PCl₅. ### Step-by-Step Solution: 1. **Identify the Hybridization**: - PCl₅ has a phosphorus atom at the center surrounded by five chlorine atoms. The hybridization of phosphorus in PCl₅ is **sp³d**. This indicates that one s orbital, three p orbitals, and one d orbital are mixed to form five equivalent hybrid orbitals. 2. **Determine the Molecular Geometry**: ...
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PRADEEP-P-BLOCK ELEMENTS -NCERT QUESTIONS AND EXERCISES WITH ANSWERS
  1. In what way can it be proved that PH(3) is basic in nature ?

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  2. Why does PCI(3) fume in moisture ?

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  3. Are all the five bonds in PCI(5) equivalent ? Justify.

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  4. How do you account for the reducing behaviour of H(3)PO(2) ? Or (i) ...

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  5. Elements of group 16 generally show lower value of first ionization en...

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  6. Why is H(2)S less acidic than H(2)Te ?

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  7. Which form of sulphur shows paramagnetic behaviour ? Or Sulphur in t...

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  8. What happens when (i) Concentrated H2 SO4 is added to calcium fluori...

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  9. Halogens have maximum negative electron gain enthalpy. Explain why ?

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  10. Although Delta(eg)H of fluorine is less negative than that of chlorine...

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  11. Fluorine exhibits only -1 oxidation state whereas other halogens show ...

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  12. Write the balanced chemical equation for the reaction of CI(2) with ho...

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  13. When HCl reacts with finely powdered iron, it forms ferrous chloride a...

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  14. Deduce the molecular shape of BrF(3) on the basis VSEPR theory.

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  15. Why elements of group 18 known as noble gases?

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  16. Why do noble gases have low boiling points ?

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  17. Does the hydrolysis of XeF(6) leads to a redox reaction?

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  18. Why are pentahalides more covalent than trihalides?

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  19. Why is BiH(3) the strongest reducing agent amongst all the hydrides of...

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  20. Why is N(2) less reactive at room temperature ?

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