How do you account for the reducing behaviour of `H_(3)PO_(2)` ?
Or (i) Draw the structure of phosphinic acid `(H_(3)PO_(2))`.
(ii) Write a chemical reaction for its use as a reducing agent.

Explanation

To account for the reducing behavior of phosphinic acid (H₃PO₂), we can follow these steps:

### Step 1: Draw the Structure of H₃PO₂
Phosphinic acid (H₃PO₂) has the following structure:
- The central phosphorus (P) atom is bonded to one oxygen (O) atom via a double bond (P=O).
- It is also bonded to one hydroxyl group (–OH).
- Additionally, it has two hydrogen (H) atoms bonded directly to the phosphorus atom.

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