Does the hydrolysis of `XeF_(6)` leads to a redox reaction?

Explanation

Complete hydroysis of `XeF_(6)` gives `XeO_(3)`
`overset(+6)(XeF_(6))+3H_(2)O rarr overset(+6)(XeO_(3))+6 HF`
On the other hand, partial hydrolysis of `XeF_(6)` gives `XeOF_(4) and XeO_(2)F_(2)`
`overset(+6)(Xe)overset(-1)(F_(6))+overset(+1)(H_(2))overset(-2)(O) rarr overset(+6)(Xe)overset(-2)(O)overset(-1)(F_(4))+overset(+1)(2H)overset(-1)(F)," "overset(+6)(Xe)overset(-1)(F_(6))+overset(+1)(2H_(2))overset(-2)(O) rarr overset(+6)(Xe)overset(-2)(O_(2))overset(-1)(F_(2))+overset(+1)(4H)overset(-1)(F)`
Since the oxidation states of all the elements in the products of hydrolysis and reactants remain the same, therefore, it is not a redox reaction.