White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of `HCl` obtained by the hydrolysis of the product formed by the reaction of `62` g of white phosphorus with chlorine in the presence of water.

Explanation

The chemical equations for the reactions involved are :
`{:(" "P_(4) + 6 Cl_(2)rarr 4 PCl_(3)),(" "PCl_(3) + 3 H_(2)O rarr H_(3)PO_(3) + 3 HCl xx 4),(bar(underset(4 xx 31 = 124 g)(P_(4))+ 6 Cl_(2) + 12 H_(2)O rarr 4 H_(3)PO_(3) + underset(12 xx 36.5 g)(12 HCl))):}`
Now 124 g of white P give HCl = `12 xx 36.5 g`
`therefore` 62 g of white P will give HCl `= (12 xx 36.5)/(124) xx 62` = 219 g