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On heating lead (II) nitrate gives a bro...

On heating lead (II) nitrate gives a brown gas " A". The gas " A" on cooling changes to colourless solid "B" . Solid B on heating with NO changes to a blue solid 'C . Identify ' A', 'B' and' C and also write reactions involved and draw the structures of 'B' and 'C' .

Text Solution

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(i) Since lead (II) nitrate on heating gives a brown gas 'A', therefore, gas 'A' must be nitrogen dioxide `(NO_(2))`.
`underset("Lead (II) nitrate")(2Pb(NO_(3))_(2)) overset(Delta, 673 K)rarr 2 PbO + underset("Brown gas (A)")(4 NO_(2))+O_(2)`
(ii) Thre brown gas 'A' on cooling dimerises to give a colourless solid 'B', therefore 'B' must be `N_(2)O_(4)` (dinitrogen tetroxide).
`2 NO_(2) underset("On heating")overset("On cooling")(hArr) underset("Colourless solid (B)")(2N_(2)O_(4))`
(iii) Since colourless solid 'B' on heating with NO, gives a blue solid 'C', therefore 'C' muct be dinitrogen trioxide.
`2 NO + underset("Colourless (B)")(N_(2)O_(4)) rarr underset("Blue solid (C)")(2 N_(2)O_(3))`
Thus, `A = NO_(2), B = N_(2)O_(4) and C = N_(2) O_(3)`.
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