In solution of `H_(2)SO_(4)`when `SO_(3)` is bubbled, a compound 'A' is formed, which further reacts with `H_(2)O` to give `H_(2)SO_(4)`. Explain this process with equation ?

Explanation

To explain the process where sulfur trioxide (SO₃) is bubbled into a solution of sulfuric acid (H₂SO₄), leading to the formation of a compound 'A', which further reacts with water to regenerate sulfuric acid, we can break it down into the following steps:

### Step-by-Step Solution:

1. **Bubbling SO₃ into H₂SO₄**:
When sulfur trioxide (SO₃) is bubbled into a concentrated solution of sulfuric acid (H₂SO₄), a compound known as oleum or pyrosulfuric acid is formed. The reaction can be represented as:
\[
\text{SO}_3 (g) + \text{H}_2\text{SO}_4 (l) \rightarrow \text{H}_2\text{S}_2\text{O}_7 (l)
...