The reaction between `NH_(2)^(-) and N_(2)O` gives

Options

A. NO
B. `N_(3)^(-)`
C. `N_(2)O_(5)`
D. `NH_(2)NH_(2)`

Explanation

To solve the question regarding the reaction between \( \text{NH}_2^- \) (amide ion) and \( \text{N}_2\text{O} \) (nitrous oxide), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are \( \text{NH}_2^- \) (amide ion) and \( \text{N}_2\text{O} \) (nitrous oxide).

2. **Write the Reaction**:
- The reaction can be written as:
\[ \text{NH}_2^- + \text{N}_2\text{O} \rightarrow ? \]

3. **Determine the Products**:
- The amide ion \( \text{NH}_2^- \) acts as a nucleophile and will react with the nitrous oxide. The expected product of this reaction is \( \text{N}_3^- \) (azide ion) and water.
- Therefore, the balanced equation for the reaction is:
\[ \text{NH}_2^- + \text{N}_2\text{O} \rightarrow \text{N}_3^- + \text{H}_2\text{O} \]

4. **Conclusion**:
- The final products of the reaction are \( \text{N}_3^- \) (azide ion) and \( \text{H}_2\text{O} \) (water).

### Final Answer:
The reaction between \( \text{NH}_2^- \) and \( \text{N}_2\text{O} \) gives \( \text{N}_3^- \) and \( \text{H}_2\text{O} \).

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