The reaction of white phosphorus with aqueous `NaOH` gives phosphine along with another phosphorus containing compound. The reacation type, the oxidation states of phosphorus in phosphine and the other product are respectvely:

Options

A. redox reaction , -3 and -5
B. redox reaction , +3 and +5
C. disproportionation reaction , -3 and -5
D. disproportionation reaction , -3 and +1

Answer

D

Explanation

`overset(0)(P_(4))+3NaOH + 3H_(2)O rarr 3NaH_(2) overset(+1)(PO_(2))+overset(-3)(PH_(3))`
It is a disproportionation reaction. In this reaction, oxidation state of P increases from 0 in `P_(4)` to +1 in `NaH_(2)PO_(2)` and decreases from 0 in `P_(4)` to -3 in `PH_(3)`.