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Among the following which one is wrong s...

Among the following which one is wrong statement ?

A

`PH_(5) and BiCl_(5)` do not exist

B

`p pi - d pi` bonds are present in `SO_(2)`

C

`SeF_(4) and CH_(4)` have same shape

D

`I_(3)^(+)` has bent geometry

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement among the given options is incorrect, let's analyze each statement step by step: 1. **Statement 1: pH 5 and BCl5 do not exist.** - **Analysis:** BCl5 (Boron Trichloride) is a well-known compound. However, it is important to note that BCl5 does not exist under normal conditions due to steric hindrance. This statement is correct. 2. **Statement 2: P pi d pi bonds are present in SO2.** - **Analysis:** Sulfur dioxide (SO2) has a bent molecular geometry and involves double bonds between sulfur and oxygen. However, the bonding in SO2 primarily involves p orbitals rather than d orbitals. Therefore, this statement is incorrect. 3. **Statement 3: SF4 and CH4 have the same shape.** - **Analysis:** CH4 (Methane) has a tetrahedral shape, while SF4 (Sulfur Tetrafluoride) has a seesaw shape due to the presence of lone pairs. This statement is incorrect. 4. **Statement 4: I3 has bent geometry.** - **Analysis:** The I3- ion (triiodide) does indeed have a bent geometry due to the presence of lone pairs on the central iodine atom. This statement is correct. **Conclusion:** - The wrong statement among the given options is **Statement 2: P pi d pi bonds are present in SO2.**

To determine which statement among the given options is incorrect, let's analyze each statement step by step: 1. **Statement 1: pH 5 and BCl5 do not exist.** - **Analysis:** BCl5 (Boron Trichloride) is a well-known compound. However, it is important to note that BCl5 does not exist under normal conditions due to steric hindrance. This statement is correct. 2. **Statement 2: P pi d pi bonds are present in SO2.** - **Analysis:** Sulfur dioxide (SO2) has a bent molecular geometry and involves double bonds between sulfur and oxygen. However, the bonding in SO2 primarily involves p orbitals rather than d orbitals. Therefore, this statement is incorrect. ...
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