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Match the interhalogen compounds of colu...

Match the interhalogen compounds of column-I with the geometry in column-II and assign the correct code.
`{:(,"Column I",,"Column II"),((A),XX',(i),"T-shape"),((B),XX'_(3),(ii),"Pentagonal bipyramidal"),((C),XX'_(5),(iii),"Linear"),((D),XX'_(7),(iv),"Square pyramidal"),(,,(v),"Tetrahedral"):}`

A

`{:(,A,B,C,D),((a),(iii),(i),(iv),"(ii)"):}`

B

`{:(,A,B,C,D),((b),(v),(iv),(iii),"(ii)"):}`

C

`{:(,A,B,C,D),((c),(iv),(iii),(ii),"(i)"):}`

D

`{:(,A,B,C,D),((d),(iii),(iv),(i),"(ii)"):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching interhalogen compounds from Column I with their corresponding geometries in Column II, we need to analyze the hybridization and molecular geometry of each compound based on the number of valence electrons contributed by the halogens involved. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Valence Electrons:** - For interhalogen compounds of the form XX', where X and X' are halogens, we need to determine the number of valence electrons. - Each halogen (X) has 7 valence electrons. Therefore, for compounds like XX', XX3, XX5, and XX7, we can calculate the total number of valence electrons. 2. **Determine the Geometry for Each Compound:** - **(A) XX' (2 atoms)** - Total valence electrons = 7 (X) + 7 (X') = 14 - Hybridization = 14/2 = 7 (sp3d3) - Geometry = Linear (since there are no lone pairs) - **Match: (A) → (iii) Linear** - **(B) XX3 (4 atoms)** - Total valence electrons = 7 (X) + 3 (X') = 10 - Hybridization = 10/2 = 5 (sp3d) - Geometry = T-shaped (3 bond pairs + 2 lone pairs) - **Match: (B) → (i) T-shape** - **(C) XX5 (6 atoms)** - Total valence electrons = 7 (X) + 5 (X') = 12 - Hybridization = 12/2 = 6 (sp3d2) - Geometry = Square pyramidal (5 bond pairs + 1 lone pair) - **Match: (C) → (iv) Square pyramidal** - **(D) XX7 (8 atoms)** - Total valence electrons = 7 (X) + 7 (X') = 14 - Hybridization = 14/2 = 7 (sp3d3) - Geometry = Pentagonal bipyramidal (7 bond pairs + 0 lone pairs) - **Match: (D) → (ii) Pentagonal bipyramidal** 3. **Final Matching:** - A → (iii) Linear - B → (i) T-shape - C → (iv) Square pyramidal - D → (ii) Pentagonal bipyramidal ### Summary of Matches: - A → (iii) Linear - B → (i) T-shape - C → (iv) Square pyramidal - D → (ii) Pentagonal bipyramidal

To solve the problem of matching interhalogen compounds from Column I with their corresponding geometries in Column II, we need to analyze the hybridization and molecular geometry of each compound based on the number of valence electrons contributed by the halogens involved. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Valence Electrons:** - For interhalogen compounds of the form XX', where X and X' are halogens, we need to determine the number of valence electrons. - Each halogen (X) has 7 valence electrons. Therefore, for compounds like XX', XX3, XX5, and XX7, we can calculate the total number of valence electrons. ...
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