`{:(MnO_(2) + HCl overset(Delta)rarr A(g)),(A(g) + F_(2)(excess)overset(573 K)rarr B(g)),(B(l) + U(s) rarr C(g) + D(g)):}`
The gases A, B, C and D are respectively

Options

A. `Cl_(2), ClF, UF_(6), ClF_(3)`
B. `Cl_(2), ClF_(3), UF_(6), ClF`
C. `O_(2), OF_(2), U_(2)O_(3), O_(2)F_(2)`
D. `O_(2), O_(2)F_(2), U_(2)O_(3), OF_(2)`

Explanation

To solve the question step by step, we will analyze the reactions provided and identify the gases A, B, C, and D.

### Step 1: Reaction of MnO2 with HCl
The first reaction is:
\[ \text{MnO}_2 + \text{HCl} \xrightarrow{\Delta} A(g) \]

When manganese dioxide (MnO2) reacts with hydrochloric acid (HCl), it produces manganese(II) chloride (MnCl2), chlorine gas (Cl2), and water (H2O). The gas produced in this reaction is:
\[ A = \text{Cl}_2 \]

### Step 2: Reaction of A with F2
The next reaction is:
\[ A(g) + F_2 \text{ (excess)} \xrightarrow{573 \text{ K}} B(g) \]

Here, A is chlorine gas (Cl2). When Cl2 reacts with excess fluorine (F2) at elevated temperatures (573 K), it forms chlorine trifluoride (ClF3), which is also a gas. Therefore:
\[ B = \text{ClF}_3 \]

### Step 3: Reaction of B with U
The final reaction is:
\[ B(l) + U(s) \rightarrow C(g) + D(g) \]

In this step, ClF3 (B) reacts with uranium (U). The reaction produces uranium fluoride (UF6) and chlorine monofluoride (ClF). Both products are gases. Therefore:
\[ C = \text{UF}_6 \]
\[ D = \text{ClF} \]

### Summary of Gases
To summarize, the gases produced in the reactions are:
- A = Cl2 (Chlorine gas)
- B = ClF3 (Chlorine trifluoride)
- C = UF6 (Uranium hexafluoride)
- D = ClF (Chlorine monofluoride)

### Final Answer
Thus, the gases A, B, C, and D are:
- A = Cl2
- B = ClF3
- C = UF6
- D = ClF