The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)`

Options

A. can be prepared by reaction of `P_(4) and HNO_(3)`
B. is diamagnetic
C. contains N-N bond
D. reacts with Na-metal producing brown gas

Answer

B, D

Explanation

`4 HNO_(3) + P_(4) O_(10) rarr 4 HPO_(3) + 2N_(2)O_(5)`
`N_(2)O_(5)` cannot be prepared by action of `HNO_(3)` on `P_(4)` but gives `H_(3)PO_(4)`
`P_(4) + 10 HNO_(3) rarr 4 H_(3)PO_(4) + 20 NO_(2) + 4 H_(2)O`
`N_(2)O_(5)` has 54 electrons `(2 xx 7 + 5 xx 8)` and hence is diamagnetic
`N_(2)O_(5)` does not contain N-N bond.
`N_(2)O_(5)` reacts with Na producing `NO_(2)`
`Na + N_(2)O_(5) rarr NaNO_(3) + NO_(2)` (brown gas)
Thus, option (b) and (d) are correct.