The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.
R, S and T, respectively, are

Options

A. `SO_(2)Cl_(2), PCl_(5) and H_(3)PO_(4)`
B. `SO_(2)Cl_(2), PCl_(3) and H_(3)PO_(3)`
C. `SOCl_(2), PCl_(5) and H_(3)PO_(2)`
D. `SOCl_(2), PCl_(5) and H_(3)PO_(4)`

Answer

A

Explanation

`{:(Cl_(2)+SO_(2)overset("charcoal")rarr underset("Sulphuryl chloride (R)")(SO_(2)Cl_(2))),(10 SO_(2)Cl_(2)+P_(4) rarr 10 SO_(2)+4PCl_(5)(S)),(underset((S))(PCl_(5))+4H_(2)O rarr 5 HCl + underset("Orthophosphoric acid (T)")(H_(3)PO_(4))):}`
Thus, R, S, and T are respectively `SO_(2)Cl_(2), PCl_(5) and H_(3)PO_(4)` and hence option (a) is correct.