Match the entries of column I with appropriate entries of coloumn II and choose the correct option out of the four options (a), (b), (c) and (d) given at the end of each question.
`{:(,"Column I",,"Column II"),((A),PCl_(5),(p),"Angular"),((B),IF_(7),(q),"Pyramidal"),((C),H_(3)O^(+),(r),"Trigonal bipyramidal"),((D),ClO_(2),(s),"Pentagonal bipyramidal"):}`

Options

A. A-r, B-s, C-q, D-p
B. A-r, B-q, C-p, D-s
C. A-p, B-s, C-q, D-r
D. A-s, B-p, C-r, D-q

Answer

To solve the problem of matching the entries of Column I with the appropriate entries of Column II, we will analyze each compound in Column I and determine its molecular geometry based on its hybridization and electron count.

### Step-by-Step Solution:

1. **Identify the compound PCl₅:**
- Valence electrons: Phosphorus (P) has 5 valence electrons, and each Chlorine (Cl) has 7 valence electrons. Thus, total = 5 + (5 × 7) = 40 electrons.
- Hybridization: The central atom (P) uses 5 orbitals for bonding, leading to sp³d hybridization.
- Geometry: The geometry for sp³d hybridization is trigonal bipyramidal.
- **Match:** A → r (Trigonal bipyramidal).

2. **Identify the compound IF₇:**
- Valence electrons: Iodine (I) has 7 valence electrons, and each Fluorine (F) has 7 valence electrons. Thus, total = 7 + (7 × 7) = 56 electrons.
- Hybridization: The central atom (I) uses 7 orbitals for bonding, leading to sp³d² hybridization.
- Geometry: The geometry for sp³d² hybridization is pentagonal bipyramidal.
- **Match:** B → s (Pentagonal bipyramidal).

3. **Identify the compound H₃O⁺:**
- Valence electrons: Oxygen (O) has 6 valence electrons, and each Hydrogen (H) has 1 valence electron. Thus, total = 6 + (3 × 1) - 1 (due to the positive charge) = 8 electrons.
- Hybridization: The central atom (O) uses 4 orbitals for bonding, leading to sp³ hybridization.
- Geometry: The geometry for sp³ hybridization is tetrahedral, but the shape is trigonal pyramidal due to the presence of a lone pair.
- **Match:** C → q (Pyramidal).

4. **Identify the compound ClO₂:**
- Valence electrons: Chlorine (Cl) has 7 valence electrons, and each Oxygen (O) has 6 valence electrons. Thus, total = 7 + (2 × 6) = 19 electrons.
- Hybridization: The central atom (Cl) uses 2 orbitals for bonding, leading to sp² hybridization.
- Geometry: The geometry for sp² hybridization is bent or angular.
- **Match:** D → p (Angular).

### Final Matches:
- A → r (PCl₅ → Trigonal bipyramidal)
- B → s (IF₇ → Pentagonal bipyramidal)
- C → q (H₃O⁺ → Pyramidal)
- D → p (ClO₂ → Angular)

### Conclusion:
The correct matching is:
- A - r
- B - s
- C - q
- D - p