2.665 g of a complex with molecular formula `CrCl_(3).6 H_(2)O` was dissolved in water. The solution was passed through a cation exchanger such that all ionizable `Cl^(-)` ions passed into the solution. The solution was collected and treated with `AgNO_(3)` solution. The precipitate of `AgCl` was filtered, dried and weighed. Its mass found to be 2.87 g. Find out the structural formula of the complex and name it on IUPAC system (Atomic mass : Cr = 52, Ag = 108, Cl = 35.5, N = 14).

Explanation

To solve the problem step by step, we will follow the outlined process to determine the structural formula and IUPAC name of the complex.

### Step 1: Determine the Molecular Mass of the Complex
The molecular formula of the complex is \( \text{CrCl}_3 \cdot 6 \text{H}_2\text{O} \).

- Atomic mass of Cr = 52 g/mol
- Atomic mass of Cl = 35.5 g/mol
- Atomic mass of H = 1 g/mol
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