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1.502 g sample of steel yields 0.259 g o...

1.502 g sample of steel yields 0.259 g of nickel dimethylglyoximate `NiC_(8)H_(14)N_(4)O_(4)` (molar mass 289 g `mol^(-1)`). What is the percentage of nickel in the steel? (Atomic mass of Ni=59)

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To find the percentage of nickel in the steel sample, we can follow these steps: ### Step 1: Calculate the amount of nickel in the nickel dimethylglyoximate (NiDMG) produced. Given that the molar mass of NiDMG is 289 g/mol and we have 0.259 g of NiDMG, we can find the amount of nickel in this sample. 1. **Calculate moles of NiDMG:** \[ \text{Moles of NiDMG} = \frac{\text{mass of NiDMG}}{\text{molar mass of NiDMG}} = \frac{0.259 \, \text{g}}{289 \, \text{g/mol}} \approx 0.000896 \, \text{mol} ...
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