`Ag^(+)+hArr|Ag(NH_(3))_(2)|^(+), k_(1) = 6.8 xx 10^(-3)`
`[Ag(NH_(3))]^(+) + NH_(3)hArr |Ag(NH_(3))_(2)|, k_(2) = 1.6xx10^(-3)`
Then the formation constant or `|Ag(NH_(3))_(2)|^(+)` is

Options

A. `1.08xx10^(-7)`
B. `1.08xx10^(-5)`
C. `1.08xx10^(-9)`
D. none of these

Answer

B

Explanation

As the reaction takes placein two steps.
`beta=beta_(1)xxbeta_(2)=(6.8xx10^(-3))xx(1.6xx10^(-3))=10.8xx10^(-6)=1.08xx10^(-5)`