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[NiCl(4)]^(2-) is paramagnetic while [Ni...

`[NiCl_(4)]^(2-)` is paramagnetic while `[Ni(CO)_(4)]` is diamagnetic though both are tetrahedral. Why?

Text Solution

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In `[NiCl_(4)]^(2-)`, Ni is +2 oxidation state with the configuration `3d^(8)4s^(0)` . `Cl^(-)` is weak ligand. It cannot pair up the electrons in 3d orbitals. Hence, it is paramagnetic. In `[Ni(CO)_(4)]`, Ni is in zero oxidation state with the configuration `3d^(8)4s^(2)`. In the presence of `CO` ligand, the 4s electrons shift to 3d to pair up 3d electrons. Thus, there is no unpaired electron present. Hence, it is diamagnetic.
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Knowledge Check

  • CuSO_4 is paramagnetic while ZnSO_4 is diamagnetic because

    A
    `Cu^(2+)` ion has `3d^9` configuration while `Zn^(2+)` ion has `3d^(10)` configuration
    B
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    D
    `CuSO_4` is blue in colour while `ZnSO_4` is white.

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