The sum of coordination number and oxidation number of the metal M in the complex `[M(en)_2(C_2O_4)]Cl` (where `en` is ethylenediamine) is :

Options

A. 7
B. 8
C. 9
D. 6

Answer

C

Explanation

`[M(en)_(2)(C_(2)O_(4))]^(+)`. If oxidation no. of M is x, then `x+0+(-2)=+1orx=+3`
As en and `C_(2)O_(4)` are bidentate ligands, coordination no.=6
`therefore` Sum of oxidation no. and coordination no. = 3+6=9