The total number possible isomers for the complex compound `[Cu^(II)(NH_(3))_(4) [Pt^(II)CI_(4)]` are

Options

A. 3
B. 6
C. 5
D. 4

Answer

D

Explanation

The possible isomers of the given complex are
`[Cu(NH_(3))_(4)][PtCl_(4)], [Cu(NH_(3))_(3)Cl][PtCl_(3)(NH_(3))]`,
`[Cu(NH_(3))Cl_(3)][PtCl(NH_(3))_(3)],[CuCl_(4)][Pt(NH_(3))_(4)]`
Note. `[Cu(NH_(3))_(2)Cl_(2)] [PtCl_(2)(NH_(3))_(2)]` is not possible because in this case, there will be no cation and anion.