An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .

Options

A. 0.001
B. 0.002
C. 0.003
D. 0.01

Answer

A

Explanation

The complex is `[Co(H_(2)O)_(4)Cl_(2)]Cl`. It ionizes as `underset("1 mole")([Cr(H_(2)O)_(4)Cl_(2)])Cl iff [Cr(H_(2)O)_(4)Cl_(2)]^(+)+underset("1 mole")(Cl^(-))`
Thus, 1 mole of the complex produces 1 mole of `Cl^(-)` ions and hence will precipitate out 1 mole of AgCl.
100 mL of 0.01 M complex solution contains moles of the complex `= (0.01)/(1000)xx100=0.001` mole and will precipitate out 0.001 mole of AgCl.