Pick out the correct statement with respect to `[Mn(CN)_(6)]^(3-)`:

Options

A. It is `sp^(3)d^(2)`-hybridized and octahedral
B. It is `sp^(3)d^(2)`-hybridized and tetrahedral
C. It is `d^(2)sp^(3)`-hybridized and octahedral
D. It is `dsp^(2)`-hybridized and square planar

Answer

C

Explanation

In `[Mn(CN)_(6)]^(3-), Mn^(3+)=3d^(4)`

In presence of strong field ligand, `CN^(-)`,
`[Mn(CN)_(6)]^(3-)` =
ltbgt Thus, the complex is `d^(2)sp^(3)` hybridized having octahedral shape.