EAN of cobalt is 36 in ` [Co(NH_(3))_(2) O_(2)(en)Cl]` thus ,`O_(2) ` is

Options

A. peroxide ion
B. dioxide ion
C. superoxide ion
D. oxide ion

Answer

A

Explanation

Peroxide = `O_(2)^(2-)`, dioxide = `2 O^(2-)`, superoxide `=O_(2)^(-)`, oxide =`O^(2-)`
EAN = Z - Oxidation no. +2 `xx` coordination no.
If `O_(2)` is present as `O_(2)^(-)`, oxidation no. of Co = + 2 ltbr EAN = `27-2+2xx6=37`
If `O_(2)` is present as `O_(2)^(2-)`, oxidation no. of Co=+3
EAN=`27-3+2xx6=36`.