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Which of the following complexes have te...

Which of the following complexes have tetrahedral shape ?

A

`[Cu(NH_(3))_(4)]^(2+)`

B

`[Ni(CO)_(4)]`

C

`[NiCl_(4)]^(2-)`

D

`[Zn(NH_(3))_(4)]^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given complexes have a tetrahedral shape, we will analyze each complex one by one, focusing on their electronic configurations and hybridization. ### Step-by-Step Solution: 1. **Identify the Complexes:** - The complexes we need to analyze are: 1. Copper(II) tetraammine \([Cu(NH_3)_4]^{2+}\) 2. Nickel tetracarbonyl \([Ni(CO)_4]\) 3. Nickel(II) chloride \([NiCl_4]^{2-}\) 4. Zinc tetraammine \([Zn(NH_3)_4]^{2+}\) 2. **Analyze Copper(II) Tetraammine \([Cu(NH_3)_4]^{2+}\):** - Copper in this complex is in the +2 oxidation state. Its electron configuration is \([Ar] 3d^9\). - Ammonia (NH₃) is a strong field ligand, which causes pairing of electrons. - The hybridization is \(dsp^2\), which corresponds to a square planar geometry, **not tetrahedral**. 3. **Analyze Nickel Tetracarbonyl \([Ni(CO)_4]\):** - Nickel is in the zero oxidation state, with an electron configuration of \([Ar] 4s^2 3d^8\). - Carbon monoxide (CO) is a strong field ligand, leading to pairing of electrons. - The hybridization is \(sp^3\), which corresponds to a tetrahedral geometry. **This complex is tetrahedral.** 4. **Analyze Nickel(II) Chloride \([NiCl_4]^{2-}\):** - Nickel is in the +2 oxidation state, with an electron configuration of \([Ar] 3d^8\). - Chloride (Cl⁻) is a weak field ligand, so no pairing occurs. - The hybridization is \(sp^3\), which corresponds to a tetrahedral geometry. **This complex is tetrahedral.** 5. **Analyze Zinc Tetraammine \([Zn(NH_3)_4]^{2+}\):** - Zinc is in the +2 oxidation state, with an electron configuration of \([Ar] 3d^{10}\). - Ammonia (NH₃) is a neutral strong field ligand, but since zinc has a full d-orbital, it does not cause pairing. - The hybridization is \(sp^3\), which corresponds to a tetrahedral geometry. **This complex is tetrahedral.** ### Conclusion: The complexes that have a tetrahedral shape are: - Nickel tetracarbonyl \([Ni(CO)_4]\) - Nickel(II) chloride \([NiCl_4]^{2-}\) - Zinc tetraammine \([Zn(NH_3)_4]^{2+}\)
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  3. Which of the following complexes have tetrahedral shape ?

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  14. A metal complex having the composition Cr (NH(3))(4)Cl(2) Br has been ...

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  17. The coordination number of Ni^(2+) is 4. NiCl(2) + KCN ("excess") ra...

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  18. The coordination number of Ni^(2+) is 4. NiCl(2) + KCN ("excess") ra...

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  19. The coordination number of Ni^(2+) is 4. NiCl(2) + KCN ("excess") ra...

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  20. Match the entries of column I with appropriate entries of column II an...

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