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A,B and C are three complexes of chromiu...

`A,B` and `C` are three complexes of chromium(III) with the empirical formula `H_(12)O_(6)C_(13)Cr` All the three complexes not react with concentrated `H_(2)SO_(4)` whereas complexes `B` and `C` lose `6.75%` and `13.5%` of their original mass respectively, on treatment on treatment with conectrated `H_(2)SO_(4)` Identify `A,B` and `C` .

A

`[Cr(H_(2)O)_(4)Cl_(2)]Cl.2H_(2)O`

B

`[Cr(H_(2)O)_(3)Cl_(3)].3H_(2)O`

C

`[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O`

D

`[Cr(H_(2)O)_(6)]Cl_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`B=[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O overset(H_(2)SO_(4))rarr` one mole of `H_(2)O` is removed.
Molecular weight of the complex = 266.5
`%" loss "=(18)/(266.5)xx100=6.75%`
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A, B and C are three complexes of chromium (III) with the empirical formula H_(12)O_(6)Cl_(3)Cr . All the three complexes have water and chloride ion as ligands. Complex A does not react with concentrated H_(2)SO_(4) , whereas complexes B and C lose 6.75% and 13.5% of their original weight, respectively, on treatment with concentrated H_(2)SO_(4) . Which type of isomerism is possible in complex C?

A, B and C are three complexes of chromium (III) with the empirical formula H_(12)O_(6)Cl_(3)Cr . All the three complexes have water and chloride ion as ligands. Complex A does not react with concentrated H_(2)SO_(4) , whereas complexes B and C lose 6.75% and 13.5% of their original weight, respectively, on treatment with concentrated H_(2)SO_(4) . According to the Werner theory, the structure of complex A is represented by :

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