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{:(,"Column I",,"Column II"),(("A"),": C...

`{:(,"Column I",,"Column II"),(("A"),": CN :"^(-),(p),"Unidentate ligand"),(("B"),"glycinate",(q),"Didentate ligand"),(("C"),"ethylenediamine",(r),"Ambidentate ligand"),(("D"),"carbonate ion",(s),"Chelating ligand"):}`

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To solve the problem, we need to match the ligands in Column I with their corresponding types in Column II. Let's analyze each ligand one by one. ### Step 1: Identify the Ligands 1. **A: CN⁻ (Cyanide ion)** - CN⁻ is a unidentate ligand because it can form one bond with the metal center. 2. **B: Glycinate** - Glycinate is a bidentate ligand because it has two donor atoms (the nitrogen and one of the oxygen atoms) that can bind to the metal center. 3. **C: Ethylenediamine (en)** - Ethylenediamine is also a bidentate ligand as it contains two nitrogen atoms that can coordinate to the metal center. 4. **D: Carbonate ion (CO₃²⁻)** - The carbonate ion can act as a bidentate ligand because it can bind through two oxygen atoms. ### Step 2: Match with the Types of Ligands Now let's match each ligand with the correct type from Column II: - **A (CN⁻)**: Unidentate ligand (p) - **B (Glycinate)**: Didentate ligand (q) - **C (Ethylenediamine)**: Didentate ligand (q) - **D (Carbonate ion)**: Chelating ligand (s) ### Step 3: Final Matching Based on the above analysis, we can summarize the matching as follows: - A: CN⁻ → Unidentate ligand (p) - B: Glycinate → Didentate ligand (q) - C: Ethylenediamine → Didentate ligand (q) - D: Carbonate ion → Chelating ligand (s) ### Final Answer - A → p - B → q - C → q - D → s
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PRADEEP-CORDINATION COMPOUNDS-MCQ
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  9. Number of isomers formed by the coordination compound with the formula...

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