`{:(,"Column I",,"Column II"),(("A"),[Ni(CO)_(4)],(p),"Square planar"),(("B"),[Ni(CN)_(4)]^(2-),(q),"Tetrahedral"),(("C"),[Cu(NH_(3))_(4)]^(2+),(r),"Paramagnetic"),(("D"),[FeCl_(4)]^(2-),(s),"Diamagnetic "):}`

Answer

To solve the matching question regarding the coordination compounds in Column I with their properties in Column II, we will analyze each complex one by one.

### Step-by-Step Solution:

**Step 1: Analyze Complex A - [Ni(CO)4]**
- **Ligand Type**: CO is a neutral ligand.
- **Oxidation State of Ni**: Since CO is neutral, the oxidation state of Ni is 0.
- **Electron Configuration**: Ni in its elemental state has the configuration [Ar] 4s² 3d⁸.
- **Hybridization**: The presence of four ligands (CO) suggests sp³ hybridization, leading to a tetrahedral geometry.
- **Magnetism**: Since all electrons are paired, it is diamagnetic.
- **Match**: A → (p) Square planar, (s) Diamagnetic.

**Step 2: Analyze Complex B - [Ni(CN)4]²⁻**
- **Ligand Type**: CN⁻ is a strong field ligand.
- **Oxidation State of Ni**: The overall charge is -2, so Ni is in the +2 oxidation state.
- **Electron Configuration**: Ni²⁺ has the configuration [Ar] 3d⁸.
- **Hybridization**: The strong field ligand CN⁻ causes pairing of electrons, leading to dsp² hybridization and a square planar geometry.
- **Magnetism**: Since all electrons are paired, it is diamagnetic.
- **Match**: B → (q) Tetrahedral, (s) Diamagnetic.

**Step 3: Analyze Complex C - [Cu(NH₃)₄]²⁺**
- **Ligand Type**: NH₃ is a neutral ligand.
- **Oxidation State of Cu**: The overall charge is +2, so Cu is in the +2 oxidation state.
- **Electron Configuration**: Cu²⁺ has the configuration [Ar] 3d⁹.
- **Hybridization**: With four ligands (NH₃), the hybridization is dsp², leading to a square planar geometry.
- **Magnetism**: There is one unpaired electron, making it paramagnetic.
- **Match**: C → (r) Paramagnetic.

**Step 4: Analyze Complex D - [FeCl₄]²⁻**
- **Ligand Type**: Cl⁻ is a weak field ligand.
- **Oxidation State of Fe**: The overall charge is -2, so Fe is in the +2 oxidation state.
- **Electron Configuration**: Fe²⁺ has the configuration [Ar] 3d⁶.
- **Hybridization**: The weak field ligand Cl⁻ does not cause pairing, leading to sp³ hybridization and a tetrahedral geometry.
- **Magnetism**: There are unpaired electrons, making it paramagnetic.
- **Match**: D → (s) Diamagnetic.

### Final Matches:
- A → (p) Square planar, (s) Diamagnetic
- B → (q) Tetrahedral, (s) Diamagnetic
- C → (r) Paramagnetic
- D → (s) Diamagnetic