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EDTA^(4-) i9s ethylenediamine tetraaceta...

`EDTA^(4-)` i9s ethylenediamine tetraacetate ion The total number of `N-CO-O` bond angles in `[Co(EDTA)]^(-1)` complex ion is .

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The correct Answer is:
8

The complex `[Co(EDTA)]^(1-)` has the structure as under :

The N-Co-O bond angles are :
(1) `angleN^(I)CoO^(I)` (2) `angleN^(I)CoO^(II)` (3) `angleN^(I)CoCO^(III)`
(4) `angle^(I)CoO^(IV)` (5) `angleN^(II)CoO^(I)` (6) `angleN^(II)CoO^(II)`
(7) `angleN^(II)CoO^(III)` (8) `angleN^(II)CoO^(IV)`
Hence, total N-Co-N bond angles = 8.
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