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In dilute aqueous H(2)SO(4) the complete...

In dilute aqueous `H_(2)SO_(4)` the complete diaquadioxalatoferrate (II) is oxidised by `MnO_(4)^(-)`. For the reaction, the ratio of the rate of change of `[H^(+)]` to the rate of change of `[MnO_(4)^(-)]` is

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The correct Answer is:
8

The given complex, `[Fe(C_(2)O_(4))(H_(2)O)_(2)]^(2-)` contains
Fe in +2 oxidation state. In acidic medium, `KMnO_(4)` oxidizes `Fe^(2+)` to `Fe^(3+)`
`MnO_(4)^(-)+8H^(+)+5Fe^(2+)rarrMn^(2+)+4H_(2)O+5Fe^(3+)`
`5Fe^(2+)-=5[Fe(C_(2)O_(4))_(2)(H_(2)O)_(2)]^(2-)`
`therefore ("Rate of change of "[H^(+)])/("Rate of change of "[MnO_(4)^(-)])=(8)/(1)=8`
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In dilute aqueous H_(2)SO_(4) the complete diaquadioxalatoferrate (II) is oxidised by MnO_(4)^(-) . For thi reaction, the ratio of the rate of change of [H^(+)] to the rate of change of [MnO_(4)^(-)] is

In basic medium, I^(-) is oxidised by MnO_(4)^(-) . In this process, I^(-) changes to :

Complete the following : 3MnO_(4)^(2-)+4H^(+) to

MnO_(4)^(2-)+H^(+) to "Product" Product is formed

In dilute alkaline solution, MnO_(4)^(-) changes to:

In a titration, H_(2)O_(2) is oxidised to O_(2) by MnO_(4)^(-) . 24 mL of 0.1M H_(2)O_(2) requires 16 mL of 0.1M MnO_(4)^(-) solution. Hence MnO_(4)^(-) changes to :

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