`CHF_(3)` is less acidic than `CHCl_(3)`. Explain.

Explanation

Due to stronger -I-effect of F than Cl, `CHF_(3)` should be more acidic than `CHCl_(3)`. But actually reverse is true. This is due to the reason that: `C Cl_(3)^(-)` left after the removal of a proton from `CHCl_(3)` is stabilized by resonance due to the presence of d-orbitals on Cl but: `CH_(3)^(-)` left after the removal of a proton from `CHF_(3)` is not stabilized by resonance due to the absence of d-orbitals.