Give the IUPAC names of the following compounds:
(i) `CH_(3)CH(Cl)CH(Br)CH_(3)`
(ii) `CHF_(2)CBrClF`
(iii) `ClCH_(2)C-=C CH_(2)Br`
(iv) `(C Cl_(3))C Cl`
(v) `CH_(3)C(pClC_(6)H_(4))_(2)CH(Br)CH_(3)`
(vi) `(CH_(3))_(3) C CH=C(Cl)C_(6)H_(4)I-p`

Explanation

To provide the IUPAC names for the given compounds, we will follow a systematic approach for each one. Below are the step-by-step solutions:

### (i) CH₃CH(Cl)CH(Br)CH₃

1. **Identify the longest carbon chain**: The longest chain has 4 carbon atoms (butane).
2. **Identify substituents**: There are two substituents: Cl (chlorine) and Br (bromine).
3. **Number the carbon chain**: Numbering from left to right gives Cl at position 2 and Br at position 3.
4. **Write the name**: The substituents are named in alphabetical order. Thus, the name is 2-bromo-3-chlorobutane.
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