Write the isomers of the compound having formula `C_(4)H_(9)Br`.

Explanation

D.B.E. for `C_(4)H_(9)Br=(4(4-2)+9(1-2)+1(1-2))/(2)+1=0`
thus, the compound is saturated. It has the following four isomers:
(i) `underset("1-Bromobutane")(CH_(3)CH_(2)CH_(2)CH_(2)Br)`
(ii) `underset("2-Bromobutane")(CH_(3)CH_(2)-underset(Br)underset(|)overset(2)(C)H-overset(1)(C)H_(3))`
(iii) `underset("1-Bromo-2-methylpropane")(overset(3)(C)H_(3)-overset(CH_(3))overset(|)(.^(2)C)H-overset(1)(C)H_(2)Br)`
(iv) `underset("2-Bromo-2-methylpropane")(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-Br)`