Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements.

Options

A. both the compounds form same product on treatment with alcoholic KOH
B. Both the compounds form same product on treatment with alcoholic KOH
C. Both the compounds form same product on reduction.
D. Both the compounds are optically active.

Answer

A, C

Explanation

Both the compounds form same product. i.e., acetylene on treatment with alc. KOH
`underset("Ethylene chloride")(ClCH_(2))-CH_(2)Cl" or "underset("Ethylidene chloride")(CH_(3)CHCl_(2)) underset(-2" HCl")overset("Alc. KOH")to underset("Acetylene")(HC-=CH)`
(b) both the compounds form different products on treatment with aq. NaOH.
`underset("Ethylene chloride")({:(CH_(2)Cl,),(|,),(CH_(2)Cl,):})overset(Aq." "NaOH)to underset("Ethylene glycol")({:(CH_(2)OH,),(|,),(CHCl_(2),):}) overset(Aq.NaOH)to {:(CH_(3),),(|,),(CH(OH)_(2),):}underset(-H_(2)O)to underset("Acetaldehyde")({:(CH_(3),),(|,),(CHO,):})`
(c) Both the compounds form same product, i.e., ethane on reduction.
`ClCH_(2)CH_(2)Cl` or `CH_(3)CHCl_(2) overset("Reduction")to underset("Ethane")(CH_(3)-CH_(3))+2HCl`
(d) Both the comounds are not optically active.
thus, options (a) and (c) are correct.