Arrange the following in order of their
Increasing basicity: `H_(2)O, OH^(-), CH_(3)OH, CH_(3)O^(-)`

Explanation

Consider the reaction, `CH_(3)O^(-)+H_(2)OtoCH_(3)OH+OH^(-)`. Since a stronger base displaces a weaker base from its compounds, therefore, `CH_(3)O^(-)` is a stronger base than `OH^(-)` ion and `CH_(3)OH` is a stronger base than `H_(2)O`. Thus, the order of increasing basicity is: `H_(2)O,CH_(3)OH,OH^(-),CH_(3)O^(-)`