One mole of an organic compound (A) having M.F. `C_(2)H_(6)O` reacts with MeMgI to liberate one mole of methane. (A) reacts with `CH_(3)COCl` to yield a sweet smelling liquid (B). Identify (A) and (B).

Explanation

To solve the problem, we need to identify the organic compound (A) with the molecular formula C2H6O that reacts with MeMgI (methylmagnesium iodide) to liberate one mole of methane (CH4) and then reacts with CH3COCl (acetyl chloride) to yield a sweet-smelling liquid (B).

### Step-by-Step Solution:

1. **Identify Compound A:**
- The molecular formula of compound A is C2H6O. This formula suggests that it could be either an alcohol or an ether.
- Since it reacts with MeMgI to liberate methane, it indicates that A is likely an alcohol. This is because Grignard reagents (like MeMgI) react with alcohols to produce alkanes and magnesium alkoxides.
- The only alcohol that fits the formula C2H6O and can react with MeMgI to release methane is **ethanol (C2H5OH)**.
...