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What is Z in the following sequence of r...

What is Z in the following sequence of reactions?
`Z overset(PCl_(3))toX overset(alc.KOH)to Y underset((ii)H_(2)O boil)overset((i)Conc.H_(2)SO_(4))toZ`

A

`CH_(3)CH_(2)CH_(2)OH`

B

`CH_(3)CHOHCH_(3)`

C

`CH_(3)CH_(2)CH_(2)CH_(2)OH`

D

`(CH_(3))_(3)C CH_(2)OH`

Text Solution

Verified by Experts

The correct Answer is:
B
Since alkenes give Markovnikov's addition products, therefore, `1^(@)` alcohols (a), (c) and (d) cannot be obtained by hydration. Thus, Z must be 2-propanol, i.e.,
`underset((Z))(CH_(3)CHOHCH_(3))overset(PCl_(5))to underset((X))(CH_(3)CHClCH_(3))underset(-HCl)overset("Alc. KOH")to underset((Y))(CH_(3)CH=CH_(2)) underset((ii)" "H_(3)O^(+))overset((i)" conc. "H_(2)SO_(4))to underset((Z))(CH_(3)CHOHCH_(3))`
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