Which of the estes shown, after reduction with `LiAlH_(4)` and aqueous workup, will yield two molecules of only a single alcohol ?

Options

A. `C_(6)H_(5)COOC_(6)H_(5)`
B. `CH_(3)CH_(2)COOCH_(2)CH_(3)`
C. `C_(6)H_(5)COOCH_(2)C_(6)H_(5)`
D. `CH_(3)COOCH_(3)`

Answer

C

Explanation

Esters in which acyl and alkyl/aralkyl groups contain the same number of carbon atoms would give two molecules of the same alcohol, i.e.,
`C_(6)H_(5)CO OCH_(2)C_(6)H_(5) underset((ii)" "H_(3)O^(+))overset((i)" "LiAlH_(4)//ether)to underset("Benzyl alcohol")(2C_(6)H_(5)CH_(2)OH)`