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3750 mg of an alcohool reacts with requi...

3750 mg of an alcohool reacts with required amount of methyl magnesium bromide and release 140mL of methane gas at STP. The alcohol is `:`

A

ethanol

B

n-butanol

C

methanol

D

n-propanol

Text Solution

Verified by Experts

The correct Answer is:
D
140 mL of `CH_(4)` is produced from alcohol=375mg
`therefore22400`mL of `CH_(4)` is produced from alcohol`=(375)/(1000)xx(22400)/(140)=60` g `mol^(-1)`
Thus, alcohol with molecular mass=60g `mol^(-1)`
is `CH_(3)CH_(2)CH_(2)OH` (n-propanol).
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