Following compounds are given
(i) `CH_(3)CH_(2)OH`
(ii) `CH_(3)COCH_(3)`
(iii) `CH_(3)-underset(CH_(3))underset(|)(C)HOH`
(iv) `CH_(3)OH`

Options

A. (i), (iiii) and (iv)
B. only (ii)
C. (i), (ii) and (iii)
D. (i) and (ii)

Explanation

To determine which of the given compounds can give the Iodoform test, we need to analyze each compound based on its structure and the presence of specific functional groups.

### Step-by-step Solution:

1. **Identify the Compounds:**
- (i) `CH₃CH₂OH` - Ethanol
- (ii) `CH₃COCH₃` - Acetone
- (iii) `CH₃-CH(OH)-CH₃` - 2-Propanol
- (iv) `CH₃OH` - Methanol

2. **Understanding the Iodoform Test:**
- The Iodoform test is used to identify the presence of methyl ketones (R-CO-CH₃) or alcohols that can be oxidized to methyl ketones. The positive result is indicated by the formation of a yellow precipitate of iodoform (CHI₃).

3. **Analyzing Each Compound:**
- **Ethanol (CH₃CH₂OH)**: Ethanol has a primary alcohol structure. When oxidized, it can form acetaldehyde (which is not a methyl ketone), thus it does **not** give a positive Iodoform test.
- **Acetone (CH₃COCH₃)**: Acetone is a methyl ketone. It will give a positive Iodoform test.
- **2-Propanol (CH₃-CH(OH)-CH₃)**: 2-Propanol is a secondary alcohol that can be oxidized to acetone (a methyl ketone). Thus, it will also give a positive Iodoform test.
- **Methanol (CH₃OH)**: Methanol is a primary alcohol and does not have the structure to form a methyl ketone upon oxidation. Therefore, it does **not** give a positive Iodoform test.

4. **Conclusion:**
- The compounds that can give the Iodoform test are:
- Acetone (ii)
- 2-Propanol (iii)

### Final Answer:
The compounds that can give the Iodoform test are (ii) Acetone and (iii) 2-Propanol.