An organic compound X on treatment with pyridinium chlorochromate in dichloromethane gives compound Y. compound Y reaccts with `I_(2)` and alkali to form triiodomethane. The compound 'X' is

Options

A. `CH_(30)CH_(2)OH`
B. `CH_(3)CHO`
C. `CH_(3)COCH_(3)`
D. `CH_(3)COOH`

Explanation

To solve the question step by step, let's analyze the information given about the organic compound X, its reaction with pyridinium chlorochromate (PCC), and the subsequent reactions leading to the formation of triiodomethane.

### Step 1: Identify the Reaction with PCC
Pyridinium chlorochromate (PCC) is a mild oxidizing agent that is commonly used to oxidize primary alcohols to aldehydes and secondary alcohols to ketones. In this case, compound X is treated with PCC to yield compound Y.

### Step 2: Determine the Nature of Compound Y
Since compound Y reacts with iodine (I2) and alkali to form triiodomethane (CHI3), it suggests that compound Y must be a methyl ketone or an aldehyde. The reaction with iodine and alkali is known as the iodoform reaction, which specifically occurs with methyl ketones or ethanol.

### Step 3: Analyze the Possible Structures
Given that compound Y leads to the formation of triiodomethane, we can deduce that compound Y is likely to be acetaldehyde (CH3CHO) or a methyl ketone.

### Step 4: Identify Compound X
If compound Y is acetaldehyde, then compound X must be ethanol (CH3CH2OH). When ethanol is oxidized by PCC, it forms acetaldehyde.

### Step 5: Confirm the Reaction
1. Ethanol (X) is oxidized by PCC to form acetaldehyde (Y).
2. Acetaldehyde (Y) reacts with I2 and alkali to give triiodomethane (CHI3).

### Conclusion
Based on the above deductions, the compound X is ethanol (CH3CH2OH).

### Final Answer
The compound X is ethanol (C2H5OH).

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