Haloform reaction does not take place with

Options

A. acetone
B. 2-chloropropane
C. ethanol
D. methanol

Explanation

To determine which compound does not undergo the haloform reaction, we need to analyze the options provided. The haloform reaction typically occurs with methyl ketones or compounds that can be oxidized to form a methyl ketone.

### Step-by-Step Solution:

1. **Understanding the Haloform Reaction**:
The haloform reaction involves the reaction of a methyl ketone (or a compound that can be converted to a methyl ketone) with halogens (X2) in the presence of a base (OH-). The general reaction produces a haloform (like chloroform, bromoform, etc.) and a carboxylate ion.

2. **Identifying Methyl Ketones**:
Methyl ketones have the structure RCOCH3, where R can be any alkyl group. Common examples include acetone (CH3COCH3) and other similar compounds.

3. **Analyzing the Options**:
- **Option 1: Acetone (CH3COCH3)**: This is a methyl ketone and will undergo the haloform reaction.
- **Option 2: 2-Chloropropane (CH3CHClCH3)**: This compound can also undergo the haloform reaction because it can be converted to a methyl ketone upon halogenation.
- **Option 3: Ethanol (CH3CH2OH)**: Ethanol is not a methyl ketone and does not have the necessary structure to undergo the haloform reaction.
- **Option 4: Methanol (CH3OH)**: Methanol is also not a methyl ketone and will not undergo the haloform reaction.

4. **Conclusion**:
The compound that does not undergo the haloform reaction is **Methanol (CH3OH)**, as it lacks the necessary methyl ketone structure.

### Final Answer:
Methanol (CH3OH) does not undergo the haloform reaction.