Identify Z in the sequence of reactions:
`CH_(3)CH_(2)CH=CH_(2)overset(HBr//H_(2)O_(2))to Y overset(C_(2)H_(5)ON a)toZ`

Options

A. `CH_(3)-(CH_(2))_(3)-O-CH_(2)CH_(3)`
B. `(CH_(3))_(2)CH-O-CH_(2)CH_(3)`
C. `CH_(3)-(CH_(2))_(4)-O-CH_(3)`
D. `CH_(3)CH_(2)-CH(CH_(3))-O-CH_(2)CH_(3)`

Explanation

To identify compound Z in the given sequence of reactions, let's break down the steps involved in the transformations.

### Step-by-Step Solution:

1. **Starting Compound**: The starting compound is 1-butene, which can be represented as CH₃CH₂CH=CH₂.

2. **Reaction with HBr in the presence of H₂O₂**:
- When 1-butene reacts with HBr in the presence of hydrogen peroxide (H₂O₂), the addition of HBr occurs via a radical mechanism due to the peroxide effect.
- According to the anti-Markovnikov rule, the bromine atom will add to the less substituted carbon of the double bond.
- Therefore, the product Y will be 1-bromobutane (CH₃CH₂CH₂CH₂Br).

3. **Formation of Z with C₂H₅O⁻ (Ethoxide)**:
- The next step involves the reaction of 1-bromobutane with ethoxide (C₂H₅O⁻).
- Ethoxide acts as a nucleophile and will perform a nucleophilic substitution reaction, replacing the bromine atom.
- The ethoxide ion will attack the carbon bonded to the bromine, leading to the formation of an ether.

4. **Final Product Z**:
- The product Z formed from this reaction will be butyl ethyl ether, which can be represented as CH₃CH₂OCH₂CH₃.

### Conclusion:
Thus, the compound Z in the sequence of reactions is butyl ethyl ether, represented as CH₃CH₂OCH₂CH₃.