2-Methyl-2-propanol may be prepared by reacting methylmagnesium iodide with

Options

A. propanone
B. ethyl ethanoate
C. ethanal
D. ethylene oxide

Explanation

To prepare 2-Methyl-2-propanol using methylmagnesium iodide (CH3MgI), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Grignard Reagent**:
- The Grignard reagent we are using is methylmagnesium iodide (CH3MgI). This reagent acts as a nucleophile.

2. **Choose the Appropriate Carbonyl Compound**:
- To synthesize 2-Methyl-2-propanol, we need to react the Grignard reagent with a suitable carbonyl compound. The appropriate compound here is acetone (2-propanone, CH3COCH3).

3. **Nucleophilic Attack**:
- The nucleophilic carbon (from CH3MgI) attacks the electrophilic carbon of the carbonyl group in acetone. This results in the formation of a tetrahedral intermediate.

4. **Formation of Alkoxide Intermediate**:
- The attack leads to the formation of an alkoxide intermediate (CH3)2C(OH)CH3, where the oxygen now carries a negative charge.

5. **Protonation**:
- The alkoxide intermediate is then protonated during the work-up step (usually involving aqueous acid), resulting in the formation of 2-Methyl-2-propanol.

6. **Final Product**:
- The final product of this reaction is 2-Methyl-2-propanol (tert-butanol).

### Final Answer:
2-Methyl-2-propanol may be prepared by reacting methylmagnesium iodide with acetone (2-propanone).

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